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Everything posted by matevz

  1. matevz

    Specific yield

    Hey Bill, thanks. I get that, BUT the problem I have trouble understanding is that by my logic, the higher the number (i.e.: efective porosity) the FASTER you can drain the aquifer, right? But...when one inputs the number 0.05 (5%) in comparisson to 0.15 (15%) for Sy (open aquifer) in transient model you get that drainage is a lot faster with the 5%....drawdown is a lot faster in 5% that in 15%....and that i don't understand if it's correct. Thanks, m
  2. matevz

    Specific yield

    Hi all, I cant find an explanation on what is the unit that is used in specific yield filed in GMS. Is it the percentage (0-1) or soemthing else. I find getting strange result as the water gets drained faster when Sy is 0.04 in comparisson to where Sy = 0.15. Does anyone has any idea regarding that?
  3. ok, i'll do that. Thank you. m
  4. matevz

    Ranny well

    Hi all, what would be the best way to simulate Ranny well? Well with horizontal MNW2 wells or series of well in circular pattern with proportional flow? Open to ideas? m
  5. Hi alan, i would, but the file is pretty big. .Do you have any FTP?
  6. I see same setup work in Modflow 2000, but crashes in MF-2005 and MF-NWT. Ideas?
  7. Hi, when i try imodelling horizontal well using MNW2 executable always craches. When checking the model, model checker gies no errors. Is there a way to check why the run crashes? thanks, m
  8. Thanks GMS user...i'll check it out. m
  9. Hi, no i mean i can't find the actual equations on which these paramateres are calculated in GMS...
  10. Hi Sean, thanks fot the help. It works now. Do you have any idea how storage coefficient and specific yield is calculated in GMS? thanks, m
  11. Hi Sean, thanks for explanation. Coudn't i simply use Cell rewetting? What do you mean by adjusting the elevation of layers? Thanks, m
  12. I am sorry but i can't attach any file biger than 29 kb...
  13. Hi all, i am having some problem with modeling dewatering of excavation pit. I created a simple 4 layer model (with flat borders between layers). Hk for eac layers are as follows, 1e-3 m/s, 1e-6 m/s, 5e-3 m/s and 5e-3 m/s. Layers 3 and 4 are the same i just divided them, so that i coul model the depth to which sheet wall is designed. I modelled dewatering with several (around 30) pumping wells. Here comes the problem. When setting pumping rate to -0.007 m^3/s(unit) i get really small drawdown. But if i set pumping rate just a little bit higher, like -0.008 (unit) i get all DRY CELLS in layer 1 BUT AT THE SAME TIME i get all FLOODED cells in layer two?! Attached is the file with taht solution (with -0.008 m^3/s pumping rate for each well., coverage ss). Does anyone have any idea why this ahppens? Regards, m
  14. matevz

    Seep2D help

    Hi Todd, i' ve tried changeing the units. I get flowrate, but still there is no flowlines?! I've also sent the GPR file with this project to support@aquaveo.com. Hope you'll get this file... thank you matevz
  15. matevz

    Seep2D help

    Hi all, i have constructed a 2D model in GMS for calculation of SEEPAGE. I have a DAM in which water table on one side is at 171 m and on the other on 169.0 m. In dam there is a jet-grouting sheet which has a very low permitivitty. I have also 4 layers with such conductivity factor k (from top to bottom): 1) k.1 = 5 x E-5m/s, 2) k.2 = 1 x E-7m/s, 3) k.3 = 5 x E-5m/s 4) k.4 = 1 x E-9 m/s The situation is shown in the attached picture. When I run the model i get the result for total flowrate = 0.0000 m^3/s/m. Why? Also i do not get any flow lines? WhY? I have tried to figure this out, but i cant. So any help is very appreciated. Thank you, m
  16. Hi all, I have such problem : A dam in which i have a water table on one side (lake), the core of the dam (which should be sealed but it is not) and the springs on the other side. Now my question is : is it possible to calculate flowlines in GMS (MODFLOW or SEEP2D) and the speed of the exiting water? Any help would be greatly appreciated, Thank you, matevz
  17. Oh....ok than i'll ask for a password...hope that 7.0 non-beta wil work with the hardlock.
  18. I am having the same problems. When it start GMS want to enable the software. When i choose hardlock it starts installing some drivers and than it shuts down. to Any suggestions?
  19. Hi Shabbir, I have modelled few contruction pits, also with diaphragm wall. The way that i did it is : - i constructed a model with as much layers that were found - made an extra layer, that extended to the ending depth of diaphragm wall - used the starting water table elevation - using well or general head package (GHP) simulate the pumping of water until i get the groundwater table to the desired dapth If you have any question you can also send me an email on : matevz (dot) pavlic (at) gi-zrmk (dot) si m
  20. Hi, this is addressed to developers : " Do you know or have an estimate on when the label problem with Vista will be fixed?" Thanks, matevz
  21. Can you maybe give an estimate (one month/one year)? thanks, matevz
  22. Hi, I hope I can explain this.... I made a small model with an area where I want to lower the water table for about 3,6 meters. The permeability coeff. is around 5*10^-3. According to this the radious of influence is fairly long if I simulate pumping out with well. Now, the problem is, as I understand, that for model to be realistic i should have a model which size is bigger the the radius of influence of a well. Because if I define SPECIFIED HEAD on the borders of a model, i get an unrealisticly big amout of water that should be pumped out of model, because MODFLOW is of course maintaining the water table as specified. Now, my question is : Is there any other way that I could simulate pumping out of a small model, which radius of influence is bigger than the model? I hope i explained ok. thanks for any help or hints, m
  23. Hi, does anyone knoe why there is so much difference between model computation and a calculation via some empirical equations? For example, i calculated the amount of water that has to be pumped out of several wells in a raster (using the 3,6 drawdown and k=6*10-3m/s) with this formula : Q=k*(H^2-h^2)/(0.733*log(R/re)) where re - is the ekvivalent radius of the area where water needs to be lowered R - is radious of influence H - 15m h - 11.4 The result with this equation is Q = 357 L/s When I use same numbers in model i get Q = 1.4 m^3/s (1400 L/s)? I know the model uses more parameters and the numbers shouldnt be the same completely but this is more that 300% increase! Does anyone has any idea? Thanky, matevz
  24. matevz

    Specified head

    Hi, thank a lot for that link. I wish i had that PDF sooner matevz
  25. matevz

    Specified head

    Hi, ok, i guessed that right. What u get out of this is the amount of water that has to be taken out with this drainage system, as i understand? Buit that meaning that the pipes are completely hollow? I dont get this conductance estimation...i must be really dumb! thank man! m
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